(10x^2-4x)/2=115

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Solution for (10x^2-4x)/2=115 equation:


x in (-oo:+oo)

(10*x^2-(4*x))/2 = 115 // - 115

(10*x^2-(4*x))/2-115 = 0

(10*x^2-4*x)/2-115 = 0

(10*x^2-4*x)/2+(-115*2)/2 = 0

10*x^2-4*x-115*2 = 0

10*x^2-4*x-230 = 0

10*x^2-4*x-230 = 0

2*(5*x^2-2*x-115) = 0

5*x^2-2*x-115 = 0

DELTA = (-2)^2-(-115*4*5)

DELTA = 2304

DELTA > 0

x = (2304^(1/2)+2)/(2*5) or x = (2-2304^(1/2))/(2*5)

x = 5 or x = -23/5

2*(x+23/5)*(x-5) = 0

(2*(x+23/5)*(x-5))/2 = 0

(2*(x+23/5)*(x-5))/2 = 0 // * 2

2*(x+23/5)*(x-5) = 0

( 2 )

2 = 0

x belongs to the empty set

( x+23/5 )

x+23/5 = 0 // - 23/5

x = -23/5

( x-5 )

x-5 = 0 // + 5

x = 5

x in { -23/5, 5 }

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